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Upload File and Response

Dec 29, 2010 at 2:30 PM

Hello, i've want to upload a file to the web server and/or show a response text at the page that said "Upload success" or no. How can i do it. I've a version 2.0 of WebServer


In server

           var server = new Server();

           var module = new FileModule();
            module.Resources.Add(new FileResources("/", "C:\\temp\\"));


           HttpListener ss =   HttpListener.Create(IPAddress.Any, 8085);
            ss.RequestReceived += new EventHandler<RequestEventArgs>(ss_RequestReceived);

            // use one http listener.

            // start server, can have max 5 pending accepts.


        static void ss_RequestReceived(object sender, HttpServer.RequestEventArgs e)

// check if file is upload.html


           e.Request.Body.Seek(0, SeekOrigin.Begin);

            byte[] body = new byte[e.Request.Body.Length];

            e.Request.Body.Read(body, 0, (int)e.Request.Body.Length);*/

      ///SAve file function





in index.html something like this


<form enctype="multipart/form-data"  method = "post">
    <input id="my_file_element" type="file" name="file_1" >
    <input type="submit">


How can i do show in index.html a successful message string ? and this mode is correct to upload a file with WebServer ?


bye and tnx





Dec 29, 2010 at 3:08 PM

Check the following property: 


Dec 29, 2010 at 3:14 PM

Tnx for quick reply, but  the e.Request.Files["file_1"] is ever null



Dec 29, 2010 at 6:52 PM

The http listener do not do anything with the request as you have noticed.

Alternative one:

Switch and use Server class instead. It decodes all bodies.

Alternative two:

Use MultiPartDecoder to decode the body:

var decoder = new MultiPartDecoder();
decoder.Decode(e.Request.Body, e.Request.ContentType, e.Request.Encoding);

Make sure that the stream is at the beginning first.